Circle Game

在坐标轴上，有一个以 $(0,0)$ 为圆点，$d$ 为半径的圆。 现在 Ashish 和 Utkarsh 玩游戏，Ashish 是先手。 在 $(0,0)$ 处有一颗棋子，两人轮流将棋子向上或向右移动 $k$ 个单位，棋子不能移出圆，谁无法移动谁输。 Translate by leapfrog

Utkarsh is forced to play yet another one of Ashish's games. The game progresses turn by turn and as usual, Ashish moves first. Consider the 2D plane. There is a token which is initially at $ (0,0) $ . In one move a player must increase either the $ x $ coordinate or the $ y $ coordinate of the token by exactly $ k $ . In doing so, the player must ensure that the token stays within a (Euclidean) distance $ d $ from $ (0,0) $ . In other words, if after a move the coordinates of the token are $ (p,q) $ , then $ p^2 + q^2 \leq d^2 $ must hold. The game ends when a player is unable to make a move. It can be shown that the game will end in a finite number of moves. If both players play optimally, determine who will win.

The first line contains a single integer $ t $ ( $ 1 \leq t \leq 100 $ ) — the number of test cases. The only line of each test case contains two space separated integers $ d $ ( $ 1 \leq d \leq 10^5 $ ) and $ k $ ( $ 1 \leq k \leq d $ ).

For each test case, if Ashish wins the game, print "Ashish", otherwise print "Utkarsh" (without the quotes).

5
2 1
5 2
10 3
25 4
15441 33

Utkarsh
Ashish
Utkarsh
Utkarsh
Ashish

In the first test case, one possible sequence of moves can be $ (0, 0) \xrightarrow{\text{Ashish }} (0, 1) \xrightarrow{\text{Utkarsh }} (0, 2) $ . Ashish has no moves left, so Utkarsh wins.