CF2006E Iris's Full Binary Tree
Description
Iris likes full binary trees.
Let's define the depth of a rooted tree as the maximum number of vertices on the simple paths from some vertex to the root. A full binary tree of depth $ d $ is a binary tree of depth $ d $ with exactly $ 2^d - 1 $ vertices.
Iris calls a tree a $ d $ -binary tree if some vertices and edges can be added to it to make it a full binary tree of depth $ d $ . Note that any vertex can be chosen as the root of a full binary tree.
Since performing operations on large trees is difficult, she defines the binary depth of a tree as the minimum $ d $ satisfying that the tree is $ d $ -binary. Specifically, if there is no integer $ d \ge 1 $ such that the tree is $ d $ -binary, the binary depth of the tree is $ -1 $ .
Iris now has a tree consisting of only vertex $ 1 $ . She wants to add $ n - 1 $ more vertices to form a larger tree. She will add the vertices one by one. When she adds vertex $ i $ ( $ 2 \leq i \leq n $ ), she'll give you an integer $ p_i $ ( $ 1 \leq p_i < i $ ), and add a new edge connecting vertices $ i $ and $ p_i $ .
Iris wants to ask you the binary depth of the tree formed by the first $ i $ vertices for each $ 1 \le i \le n $ . Can you tell her the answer?
Input Format
N/A
Output Format
N/A
Explanation/Hint
In the first test case, the final tree is shown below:
- The tree consisting of the vertex $ 1 $ has the binary depth $ 1 $ (the tree itself is a full binary tree of depth $ 1 $ ).
- The tree consisting of the vertices $ 1 $ and $ 2 $ has the binary depth $ 2 $ (we can add the vertex $ 3 $ to make it a full binary tree of depth $ 2 $ ).
- The tree consisting of the vertices $ 1 $ , $ 2 $ and $ 3 $ has the binary depth $ 2 $ (the tree itself is a full binary tree of depth $ 2 $ ).
In the second test case, the formed full binary tree after adding some vertices to the tree consisting of $ n $ vertices is shown below (bolded vertices are added):
The depth of the formed full binary tree is $ 4 $ .
In the fifth test case, the final tree is shown below:
It can be proved that Iris can't form any full binary tree by adding vertices and edges, so the binary depth is $ -1 $ .