Coprime Permutation

题意翻译

给定一个未填满的数组 $p$,求有多少种 $1\sim n$ 的排列 $p$ 满足对于任意 $i, j$,都有 $$[\gcd(i, j)=1]=[\gcd(p_i, p_j)=1]$$ 对 $10^9+7$ 取模。 $n \leq 10^6$。

题目描述

Two positive integers are coprime if and only if they don't have a common divisor greater than $ 1 $ . Some bear doesn't want to tell Radewoosh how to solve some algorithmic problem. So, Radewoosh is going to break into that bear's safe with solutions. To pass through the door, he must enter a permutation of numbers $ 1 $ through $ n $ . The door opens if and only if an entered permutation $ p_{1},p_{2},...,p_{n} $ satisfies: ![](https://cdn.luogu.com.cn/upload/vjudge_pic/CF698F/9d4538a9a97e6652f8a13f246927402ea6472421.png)In other words, two different elements are coprime if and only if their indices are coprime. Some elements of a permutation may be already fixed. In how many ways can Radewoosh fill the remaining gaps so that the door will open? Print the answer modulo $ 10^{9}+7 $ .

输入输出格式

输入格式


The first line of the input contains one integer $ n $ ( $ 2<=n<=1000000 $ ). The second line contains $ n $ integers $ p_{1},p_{2},...,p_{n} $ ( $ 0<=p_{i}<=n $ ) where $ p_{i}=0 $ means a gap to fill, and $ p_{i}>=1 $ means a fixed number. It's guaranteed that if $ i≠j $ and $ p_{i},p_{j}>=1 $ then $ p_{i}≠p_{j} $ .

输出格式


Print the number of ways to fill the gaps modulo $ 10^{9}+7 $ (i.e. modulo $ 1000000007 $ ).

输入输出样例

输入样例 #1

4
0 0 0 0

输出样例 #1

4

输入样例 #2

5
0 0 1 2 0

输出样例 #2

2

输入样例 #3

6
0 0 1 2 0 0

输出样例 #3

0

输入样例 #4

5
5 3 4 2 1

输出样例 #4

0

说明

In the first sample test, none of four element is fixed. There are four permutations satisfying the given conditions: (1,2,3,4), (1,4,3,2), (3,2,1,4), (3,4,1,2). In the second sample test, there must be $ p_{3}=1 $ and $ p_{4}=2 $ . The two permutations satisfying the conditions are: (3,4,1,2,5), (5,4,1,2,3).